(5x^2+2x)=7

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Solution for (5x^2+2x)=7 equation:


Simplifying
(5x2 + 2x) = 7

Reorder the terms:
(2x + 5x2) = 7

Remove parenthesis around (2x + 5x2)
2x + 5x2 = 7

Solving
2x + 5x2 = 7

Solving for variable 'x'.

Reorder the terms:
-7 + 2x + 5x2 = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 2x + 5x2 = 0

Factor a trinomial.
(-7 + -5x)(1 + -1x) = 0

Subproblem 1

Set the factor '(-7 + -5x)' equal to zero and attempt to solve: Simplifying -7 + -5x = 0 Solving -7 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -5x = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -5x = 0 + 7 -5x = 0 + 7 Combine like terms: 0 + 7 = 7 -5x = 7 Divide each side by '-5'. x = -1.4 Simplifying x = -1.4

Subproblem 2

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Solution

x = {-1.4, 1}

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